JCECE Medical JCECE Medical Solved Paper-2008

  • question_answer 93) The energy of second Bohr orbit of the hydrogen atom is \[-328\,\text{kJ}\,\text{mo}{{\text{l}}^{-}};\] hence the energy of fourth Bohr orbit would be

    A) \[~-41\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\]

    B)  \[-1312\text{ kJ mo}{{\text{l}}^{-1}}\]

    C)  \[-164\text{ kJ mo}{{\text{l}}^{-1}}\]

    D) \[~-82\text{ kJ mo}{{\text{l}}^{-1}}\]

    Correct Answer: D

    Solution :

     The energy of second Bohr orbit of hydrogen atom \[({{E}_{2}})\] is \[-328\text{ kJ mo}{{\text{l}}^{-1}}\] because \[{{E}_{2}}=-\frac{1312}{{{2}^{2}}}\,\text{kJ}\,\text{mo}{{\text{l}}^{-}}\] \[\therefore \] \[{{E}_{n}}=-\frac{1312}{{{n}^{2}}}\,\text{kJ}\,\text{mo}{{\text{l}}^{-}}\] If \[n=4\] \[\therefore \] \[{{E}_{4}}=-\frac{1312}{{{4}^{2}}}\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\] \[=-82\,\text{kJ}\,\text{mo}{{\text{l}}^{-1}}\]

adversite



LIMITED OFFER HURRY UP! OFFER AVAILABLE ON ALL MATERIAL TILL TODAY ONLY!

You need to login to perform this action.
You will be redirected in 3 sec spinner

Free
Videos