• # question_answer In the circuit shown in figure neglecting sourte resistance,  the voltmeter and ammeter readings will be respectively A) $0V,3A$         B) $150V,3A$ C)  $150\,V,6A$ D)  $0\,V,8A$

The voltages ${{\text{V}}_{\text{L}}}$and ${{\text{V}}_{C}}$are equal and  opposite so, voltmeter reading will be zero. Also, $R=30\,\Omega ,{{X}_{L}}={{X}_{C}}=25\,\Omega$ So, $i=\frac{V}{\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}}=\frac{V}{R}=\frac{240}{30}=8A$