question_answer

In the reaction, \[S{{O}_{2}}+2{{H}_{2}}S\xrightarrow{{}}\]\[3S+2{{H}_{2}}O\]the substance oxidised is

A) \[{{H}_{2}}S\]

B)  \[S{{O}_{2}}\]

C)  \[S\]

D)  \[{{H}_{2}}O\]

Correct Answer: A

Solution :

  \[\therefore \]\[{{\text{H}}_{\text{2}}}\text{S}\]is anode and Au is cathode.