A) \[\frac{8}{9}X\]
B) \[\frac{9}{8}X\]
C) \[\frac{5}{7}X\]
D) \[\frac{7}{5}X\]
Correct Answer: A
Solution :
Fluid resistance is given by \[R=\frac{8\eta L}{\pi {{r}^{4}}}\] When two capillary tubes of same size are joined in parallel, then equivalent fluid resistance is \[{{R}_{eq}}={{R}_{1}}+{{R}_{2}}=\frac{8\eta L}{\pi {{R}^{4}}}+\frac{8\eta \times 2L}{\pi {{(2R)}^{4}}}\] \[=\left[ \frac{8\eta L}{\pi {{R}^{4}}}\times \frac{9}{8} \right]\] Equivalent resistance becomes \[\frac{9}{8}\] times so, rate of flow will be \[\frac{8}{9}X.\]
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