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JCECE Medical JCECE Medical Solved Paper-2010

  • question_answer
    If the radius of \[{{\text{K}}^{\text{+}}}\]and \[{{F}^{-}}\]are 133 pm and 136 pm respectively, the distance between \[{{\text{K}}^{\text{+}}}\]and \[{{F}^{-}}\]in KF is

    A)  269pm       

    B)  134.5pm

    C)  136pm        

    D)  3pm

    Correct Answer: A

    Solution :

     Distance between \[{{K}^{+}}\]and \[{{F}^{-}}\]in KF \[={{r}_{{{K}^{+}}}}+{{r}_{{{F}^{-}}}}=133+136=269\,pm\]


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