JCECE Medical JCECE Medical Solved Paper-2010

  • question_answer
    The order of a reaction with rate equal to \[kC_{A}^{3/2}C_{B}^{-1/2}\]is

    A)  1

    B)  \[-\frac{1}{2}\]

    C)  \[-\frac{3}{2}\]

    D)  2

    Correct Answer: A

    Solution :

     Given, \[r=k{{C}_{A}}{{\,}^{3/2}}{{C}_{B}}^{-1/2}\] \[\therefore \]Order of reaction \[=\frac{3}{2}+\left( -\frac{1}{2} \right)\] \[=\frac{3-1}{2}=1\]


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