A) KI
B) KCNS
C) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]
D) \[B{{r}_{2}}\]
Correct Answer: A
Solution :
Ether peroxide oxidises \[\text{KI}\]into \[{{\text{I}}_{\text{2}}}\]and itself gets reduced to ether. Therefore, \[\text{KI}\]is added to remove peroxides from ethers. \[2{{I}^{-}}\xrightarrow{{}}{{I}_{2}}+2{{e}^{-}}\] Ether peroxide \[+\,2{{e}^{-}}\xrightarrow{{}}\text{ether}\,\text{+}\,{{O}_{2}}\]
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