A) 2-bromo-l-propanol
B) 3-bromo-l-propanol
C) 2-bromo-2-propanol
D) l-bromo-2-propanol
Correct Answer: D
Solution :
\[\underset{\text{propene}}{\mathop{C{{H}_{3}}CH=C{{H}_{2}}}}\,+\overset{\delta -}{\mathop{HO}}\,\overset{+}{\mathop{Br}}\,\xrightarrow{{}}\underset{1-\text{bromo}-2-\text{propanol}}{\mathop{C{{H}_{3}}\underset{OH}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{2}}Br}}\,\]The addition takes place according to Markownikoffs rule.
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