A) 7.692 rad
B) \[7.692\text{ }\pi \text{ }rad\]
C) \[\frac{7.692}{\pi }rad\]
D) \[\frac{7.692}{3\pi }rad\]
Correct Answer: B
Solution :
Phase difference \[\text{o }\!\!|\!\!\text{ =}\frac{2\pi }{\lambda }x\] \[=\frac{2\pi \times 2.1\times {{10}^{-6}}}{5460\times {{10}^{-10}}}\] \[=7.692\,\pi \,rad\]
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