A) \[\frac{{{h}^{2}}}{8\,m{{L}^{2}}}{{n}^{2}}\]
B) \[\frac{{{h}^{2}}}{4mL}{{n}^{2}}\]
C) \[\frac{h}{4mL}n\]
D) \[\frac{{{h}^{2}}}{4m{{L}^{2}}}{{n}^{2}}\]
Correct Answer: A
Solution :
One dimensional potential well \[\lambda =\frac{2L}{n}\]and \[P=\frac{nh}{2L}\] The energy for a system \[E=\frac{{{P}^{2}}}{2m}\] \[E=\frac{{{n}^{2}}{{h}^{2}}}{8{{L}^{2}}m}\]
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