JCECE Medical JCECE Medical Solved Paper-2011

  • question_answer
    The passage of current liberates \[{{\text{H}}_{\text{2}}}\]at cathode and \[\text{C}{{\text{l}}_{\text{2}}}\]at anode. The solution is

    A)  copper chloride in water

    B) \[\text{NaCl}\] in water

    C)  ferric chloride in water

    D) \[\text{AuC}{{\text{l}}_{3}}\] in water

    Correct Answer: B

    Solution :

     When current is passed in an aqueous solution of\[\text{NaCl,}\] the following reaction occur at anode and cathode:  \[NaCl\xrightarrow{{}}N{{a}^{+}}+C{{l}^{-}}\] At anode \[2C{{l}^{-}}\xrightarrow{{}}C{{l}_{2}}+2{{e}^{-}}\] At cathode \[N{{a}^{+}}+{{e}^{-}}\xrightarrow{{}}Na\] \[2{{H}^{+}}+{{e}^{-}}\xrightarrow{{}}{{H}_{2}}\] Since, the deposition potential of Na is higher, \[{{\text{H}}_{\text{2}}}\]is evolved at cathode in place of Na.


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