A) \[x=y{{z}^{2}}\]
B) \[x={{y}^{2}}z\]
C) \[{{y}^{2}}=xz\]
D) \[z={{x}^{2}}y\]
Correct Answer: A
Solution :
Given, \[x=g\,c{{m}^{2}}{{s}^{-5}}=[M{{L}^{2}}{{T}^{-5}}]\] \[y=g{{s}^{-1}}=[M{{L}^{o}}{{T}^{-1}}]\] and \[z=cm{{s}^{-2}}=[{{M}^{o}}L{{T}^{-2}}]\] Now, \[{{z}^{2}}=[{{M}^{o}}{{L}^{2}}{{T}^{-4}}]\] and \[y{{z}^{2}}=[M{{L}^{o}}{{T}^{-1}}][{{M}^{o}}{{L}^{2}}{{T}^{-4}}]\] \[=[M{{L}^{2}}{{T}^{-5}}]=x\] i.e., \[x=y{{z}^{2}}\]
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