A) \[2\,m{{s}^{-1}}\]
B) \[0.5\,m{{s}^{-1}}\]
C) \[19.6\,m{{s}^{-1}}\]
D) \[4.43\,m{{s}^{-1}}\]
Correct Answer: D
Solution :
By conservation of energy, \[mgh=\frac{1}{2}m{{v}^{2}}\] \[\Rightarrow \] \[v=\sqrt{2gh}=\sqrt{2\times 9.8\times 1}\] \[v=\sqrt{19.6}=4.43\,m{{s}^{-1}}\]
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