A) 0.8M
B) 0.6M
C) 0.4 M
D) 0.2M
Correct Answer: B
Solution :
\[{{\underset{\text{Initial}}{\mathop{{{M}_{1}}{{V}_{1}}+{{M}_{2}}V}}\,}_{2}}=\underset{\text{Final}}{\mathop{{{M}_{3}}{{V}_{3}}}}\,\] \[{{V}_{3}}={{V}_{1}}+{{V}_{2}}=800+200=1000\,mL\] \[=0.5\times 800+1\times 200\] \[={{M}_{3}}\times 1000\] \[{{M}_{3}}=\frac{600}{1000}=0.6\,M\]
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