A) \[A=1,\text{ }B=1,C=0\]
B) \[A=0,\text{ }B=0,\text{ }C=0\]
C) \[~A=0,\text{ }B=1,\text{ }C=1\]
D) \[~A=1,\text{ }B=0,\text{ }C=0\]
Correct Answer: A
Solution :
The output \[Y=\overline{(A.B).C}\] \[=(\overline{A.B})+\overline{\overline{C}}\] \[=(\overline{A.B})+C\] So,\[Y=0\]if \[A=1,B=1\]and \[C=0\]
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