JCECE Medical JCECE Medical Solved Paper-2013

  • question_answer
    If a force of 4 N is applied on a body of mass \[20\text{ }kg,\] then the work done in 3rd second will be

    A)  1.2 J

    B)  2 J

    C)  4 J               

    D)  16 J

    Correct Answer: B

    Solution :

     Here, \[a=\frac{f}{m}=\frac{4}{20}=\frac{1}{5}m/{{s}^{2}}\] Distance travelled by body in 3rd second \[{{S}_{3rd}}=0+\frac{1}{5\times 2}(2\times 3-1)\] \[=0.5\,m\] Hence, work done, \[W=f\times {{S}_{3rd}}\] \[=4\times 0.5=25\,J\]


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