JCECE Medical JCECE Medical Solved Paper-2013

  • question_answer
    For a transistor in common base, the current gain is 0.95. If the load resistance is \[400\,k\Omega \] and input resistance is \[200\,k\Omega ,\] then the voltage gain and power gain will be

    A)  1900 and ,1800

    B)  1900 and 1805

    C)  5525 and 3591.

    D)  1805 and 1900

    Correct Answer: B

    Solution :

     Given, \[\alpha =0.95,\,{{R}_{0}}=400\times {{10}^{3}}\,\Omega \] \[{{R}_{i}}=200\,\Omega \] As, voltage gain\[=\alpha \frac{{{R}_{0}}}{{{R}_{i}}}\] \[=0.95\times \frac{400\times {{10}^{3}}}{200}\] \[=1900\] Power gain = Voltage gain \[\times \]Current gain \[=1900\times 0.95\] \[=1805\]


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