A) \[\frac{1}{\sqrt{2}}\]
B) \[\frac{1}{2\sqrt{2}}\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{4}\]
Correct Answer: A
Solution :
We have\[{{v}_{1}}=\sqrt{2gh(h/2)}=\sqrt{gh}\] ?(i) and by using Bernoullis theorem \[\rho \,gh+2\rho g\left( \frac{h}{2} \right)=\frac{1}{2}(2\rho )v_{2}^{2}\] \[\Rightarrow \] \[{{v}_{2}}=\sqrt{2}gh\] ?(ii) From Eqs. (i).and (ii) \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{1}{\sqrt{2}}\]You need to login to perform this action.
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