A) 105 m/s
B) 205 m/s
C) 210 m/s
D) 250 m/s
Correct Answer: A
Solution :
Speed of thiefs car w.r.t. ground \[{{v}_{T}}=192\,km/h\] Speed of police van w.r.t. ground \[{{v}_{P}}=30\,km/h\] Speed of bullet w.r.t. police van \[{{v}_{B}}=150\,m/s=540\,km/h\] Speed with which the bullet will hit the thiefs car will be \[v={{v}_{BG}}+{{v}_{GT}}\] \[v={{v}_{B}}+{{v}_{P}}+{{v}_{T}}\] \[=540+30-192\] \[[\because \,{{v}_{G}}=-{{v}_{T}}]\] \[=378\,km/h\] \[=378\times \frac{1000}{3600}\,m/s\] \[=105\,m/s\]You need to login to perform this action.
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