| Compound | = | \[N{{H}_{3}}\] | \[P{{H}_{3}}\] | \[As{{H}_{3}}\] | \[Sb{{H}_{3}}\] |
| \[\,{{\Delta }_{diss{{(E-H)}^{H}}(kJmo{{l}^{-1}})}}\] | = | 389 | 322 | 297 | 255 |
A) \[N{{H}_{3}}\]
B) \[P{{H}_{3}}\]
C) \[As{{H}_{3}}\]
D) \[Sb{{H}_{3}}\]
Correct Answer: D
Solution :
Weaker the \[E-H\]bond, stronger the reducing agent i.e., \[Sb{{H}_{3}}.\]
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