• # question_answer A mass of 0.5 kg moving with a speed of $1.5\,\text{m}{{\text{s}}^{-1}}$on a horizontal smooth surface, collides with a nearly weightless spring of force constant$\text{k}\,\text{=}\,\text{50}\,\text{N}{{\text{m}}^{-1}}.$The maximum  compression of the spring would be A)  0.15 m              B)  0.23 m C) 1.6 m                D)  0.4 m

By the law of conservation of energy. Kinetic energy of mass = energy stored in spring $\frac{1}{2}m{{v}^{2}}=\frac{1}{2}k{{x}^{2}}$ ${{x}^{2}}=\frac{m{{v}^{2}}}{k}$ The maximum compression of the spring $x=\sqrt{\frac{m{{v}^{2}}}{k}}$ $x=\sqrt{\frac{0.5\times 1.5\times 1.5}{50}}=0.15\,m$