A) \[0.67\]
B) \[1.5\]
C) \[2.67\times {{10}^{4}}\]
D) \[9.0\times {{10}^{4}}\]
Correct Answer: C
Solution :
Partial pressure of iodine atoms \[({{p}_{1}})=\frac{40}{100}\times {{10}^{5}}\] \[=0.40\times {{10}^{5}}\,Pa\] Partial pressure of \[{{l}_{2}}(p{{l}_{2}})\] \[=\frac{60}{100}\times {{10}^{5}}Pa\] \[=0.60\times {{10}^{5}}Pa\] \[\therefore \] \[{{K}_{p}}=\frac{p_{l}^{2}}{{{p}_{{{l}_{2}}}}}=\frac{{{(0.40\times {{10}^{5}})}^{2}}}{0.60\times {{10}^{5}}}\] \[=2.67\times {{10}^{4}}\]
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