JCECE Medical JCECE Medical Solved Paper-2014

  • question_answer
    The temperature at which the mean KE of the molecules of gas is one-third of the mean KE of its molecules at \[180{{\,}^{o}}C\]is

    A) \[~-122{{\,}^{o}}C\]

    B) \[-90{{\,}^{o}}C\]

    C) \[~60{{\,}^{o}}C\]  

    D) \[151{{\,}^{o}}C\]

    Correct Answer: D

    Solution :

     Kinetic energy of a gas is directly proportional to its temperature \[\therefore \] \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] \[\frac{K}{K/3}=\frac{273+180}{{{T}_{2}}}\Rightarrow 3=\frac{453}{{{T}_{2}}}\] \[{{T}_{2}}=151{{\,}^{o}}C\]


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