JCECE Medical JCECE Medical Solved Paper-2014

  • question_answer
    X and Y, two metallic coils are arranged in such a way that, when steady change in current flowing in X coil is 4 A, change in magnetic flux associated with coil Y is 0.4Wb. Mutual inductance of the system of these coils is

    A)  0.2 H  

    B)  5H    

    C)  0.8 H  

    D)  0.1 H

    Correct Answer: D

    Solution :

     We know that, the magnetic flux associated with coil Y is directly proportional to current flowing in X coil. \[\text{o}{{\text{ }\!\!|\!\!\text{ }}_{y}}\propto {{l}_{x}}\] Here,\[\text{o}{{\text{ }\!\!|\!\!\text{ }}_{y}}=\] change in magnetic flux in coil \[Y\] \[{{l}_{x}}=\]change in current in coil X M = mutual inductance We have       \[\text{o}{{\text{ }\!\!|\!\!\text{ }}_{y}}=M{{l}_{x}}\] \[{{l}_{x}}=4A\]and \[\text{o}{{\text{ }\!\!|\!\!\text{ }}_{y}}=0.4\,Wb\] \[0.4=M\times 4\] \[M=\frac{0.4}{4}=0.1\,H\]


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