A) 6
B) 14
C) 16
D) 18
Correct Answer: B
Solution :
Magnification \[\frac{{{f}_{0}}}{{{f}_{e}}}=10\] or \[{{f}_{0}}=10{{f}_{e}}\] \[{{f}_{0}}+{{f}_{e}}=1.1\,m\] \[{{f}_{e}}+10{{f}_{e}}=1.1\times 100\,cm\] \[11{{f}_{e}}=110\] \[{{f}_{e}}=10\] Magnification least distance of distant vision \[{{M}_{0}}=\frac{{{f}_{0}}}{{{f}_{e}}}\left( 1+\frac{{{f}_{e}}}{{{f}_{s}}} \right)\] \[=10\left( 1+\frac{10}{25} \right)=10\left( \frac{35}{25} \right)=14\]
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