• # question_answer A string of length$l$fixed at one end carries a mass m at the other end. The string makes $\frac{2}{\pi }rev/s$around the horizontal axis through the fixed end as shown in the figure, the tension in the string is A) $16\,ml$             B) $6\,ml$ C) $5\,ml$            D)  $3\,ml$

$T\sin \theta =\frac{m{{v}^{2}}}{r}$ $T\cos \theta =mg$ $v=r\omega$and $\sin \theta =\frac{r}{l}$ Putting these values in Eq (i), we get $T\times \frac{r}{l}=m{{\omega }^{2}}r$ $T=m{{\omega }^{2}}l$ $\omega =2\pi n$ $T=m{{(2\pi n)}^{2}}l$ $T=m{{\left( 2\pi \times \frac{2}{\pi } \right)}^{2}}l$ $T=16\,ml$