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JCECE Medical JCECE Medical Solved Paper-2014

  • question_answer
    The values of two resistors are \[{{R}_{1}}=(6+0.3)k\Omega \] and \[{{R}_{2}}=(10\,\pm \,0.2)k\Omega .\]The percentage error in the equivalent resistance when, they are connected is parallel is

    A)  5.125%

    B)  2%    

    C)  10.125%

    D)  7%

    Correct Answer: C

    Solution :

     \[{{R}_{P}}=\frac{{{R}_{1}}{{R}_{2}}}{{{R}_{1}}+{{R}_{2}}}\] \[\frac{\Delta {{R}_{P}}}{{{R}_{P}}}=\frac{\Delta {{R}_{1}}}{{{R}_{1}}}+\frac{\Delta {{R}_{2}}}{{{R}_{2}}}+\frac{\Delta ({{R}_{1}}+{{R}_{2}})}{{{R}_{1}}+{{R}_{2}}}\] \[\frac{\Delta {{R}_{P}}}{{{R}_{P}}}=\frac{0.3}{6}+\frac{0.2}{10}+\frac{0.3+0.2}{1.16}\] \[=\frac{\Delta {{R}_{P}}}{{{R}_{P}}}\times 100\] \[=10.125%\]


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