A) 11.2
B) 22.4
C) 5.6
D) 56
Correct Answer: A
Solution :
1 molar\[{{H}_{2}}{{O}_{2}}\] solution means 1 mole (or\[34\,g\,{{H}_{2}}{{O}_{2}}\]) is present in \[\text{1}{{\text{0}}^{\text{3}}}\,\text{mL}\]solution. \[\therefore \]\[68\,g\,{{H}_{2}}{{O}_{2}}\] gives = 22400 mL of \[{{\text{O}}_{\text{2}}}\] \[\therefore \]\[\text{34}\,\text{g}\,{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}\]will gives \[\text{=}\frac{22400\,mL\times 34}{68}\] \[=11200\,mL\]of \[{{O}_{2}}\] Volume strength \[=\frac{11200}{{{10}^{3}}}=11.2\]
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