A) \[\frac{{{E}_{0}}}{4}\]
B) \[\frac{{{E}_{0}}}{2}\]
C) \[\frac{{{E}_{0}}}{8}\]
D) \[{{E}_{0}}\]
Correct Answer: B
Solution :
As, mechanical energy\[=-\frac{GMm}{2R}\] \[\Rightarrow \] \[\frac{{{E}_{0}}}{4}=-\frac{GMm}{2R}\] Kinetic energy, \[K=\frac{GMm}{2R}\] using \[E=KE+PE\] \[\frac{{{E}_{0}}}{4}=\frac{GMm}{2R}+U\] or \[U=\frac{{{E}_{0}}}{4}-\frac{GMm}{2R}=\frac{{{E}_{0}}}{4}-\left( -\frac{{{E}_{0}}}{4} \right)=\frac{{{E}_{0}}}{2}\]
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