A) \[\frac{4m}{Rh}\]
B) \[\frac{Rh}{4m}\]
C) \[\frac{3Rh}{4m}\]
D) \[\frac{4m}{3Rh}\]
Correct Answer: C
Solution :
For first line of Lyman series, \[\frac{1}{\lambda }=R\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right)=R\left( 1-\frac{1}{4} \right)=\frac{3}{4}R\] Again we have momentum, \[p=mv\]or \[\frac{h}{\lambda }=mv\]or \[v=\frac{h}{m\lambda }\] Putting the value of \[\lambda ,\] we have \[v=\frac{h}{m}\left( \frac{3}{4}R \right)=\frac{3hR}{4m}\]
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