A) boron
B) metaboric acid
C) boric anhydride
D) borax
Correct Answer: C
Solution :
\[\underset{\text{Ortho}\,\text{boric}\,\text{acid}}{\mathop{{{\text{H}}_{\text{3}}}\text{B}{{\text{O}}_{\text{3}}}}}\,\xrightarrow[\text{Above}\,\text{370}\,\text{K}]{\text{ }\!\!\Delta\!\!\text{ }}\underset{\text{Metaboric}\,\text{acid}}{\mathop{\text{HBO}}}\,\] \[\xrightarrow{\text{ }\!\!\Delta\!\!\text{ }}\underset{\text{Boric}\,\text{anhydride}}{\mathop{{{\text{B}}_{\text{2}}}{{\text{O}}_{\text{3}}}}}\,\]
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