A) \[C{{u}_{4}}A{{g}_{4}}Au\]
B) \[CuA{{g}_{3}}Au\]
C) \[cuAgCu\]
D) \[C{{u}_{4}}A{{g}_{2}}Au\]
Correct Answer: B
Solution :
Cu atoms are at eight comers of the cube. Therefore, the number of Cu atoms in the unit cell \[=\frac{8}{8}=1\] Au atoms are at the face-centre of six faces. Therefore, its share in the unit cell \[=\frac{6}{2}=3\] At atoms are at the body centres, so the number of Au atom =1 \[\therefore \]The formula of the alloy is\[\text{CuA}{{\text{g}}_{\text{3}}}\text{Au}\text{.}\]
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