Solved papers for JEE Main & Advanced JEE Main Paper (Held On 19 April 2014)

done JEE Main Paper (Held On 19 April 2014) Total Questions - 1

• question_answer1) For the decomposition of the compound, represented as\[N{{H}_{2}}COON{{H}_{4}}(s)2N{{H}_{3}}(g)+C{{O}_{2}}(g)\] the \[{{K}_{p}}=2.9\times {{10}^{-5}}at{{m}^{3}}.\] If the reaction is started with 1 mol of the compound, the total pressure at equilibrium would be :     JEE Main Online Paper (Held On 19 April 2016)
  A)
  \[1.94\times {{10}^{-2}}atm\]    
  done clear
  B)
  \[5.82\times {{10}^{-2}}atm\]
  done clear
  C)
  \[7.66\times {{10}^{-2}}atm\]    
  done clear
  D)
  \[38.8\times {{10}^{-2}}atm\]
  done clear
  View Answer play_arrow