# Solved papers for JEE Main & Advanced AIEEE Paper (Held On 11 May 2011)

### done AIEEE Paper (Held On 11 May 2011)

• question_answer1) The value of enthalpy change $(\Delta H)$for the reaction${{C}_{2}}{{H}_{5}}O{{H}_{(l)}}+3{{O}_{2(g)}}\to 2C{{O}_{2(g)}}+3{{H}_{2}}{{O}_{(l)}}$at 27°C is  $-1366.5\text{ }kJ\text{ }mo{{l}^{-1}}.$The value of internal energy change for the above reaction at this temperature will be :     AIEEE  Solved  Paper (Held On 11 May  2011)

A) -1369.0 kJ

B) -1364.0kJ

C) -1361.5 kJ

D) -1371.5 kJ

• question_answer2) Consider the reaction : $4N{{O}_{2(g)}}+{{O}_{2(g)}}\to 2{{N}_{2}}{{O}_{5}}_{(g)}'$${{\Delta }_{r}}H=-111\,kJ.$ If ${{N}_{2}}{{O}_{5(s)}}$is formed instead of ${{N}_{2}}{{O}_{5(g)}}$in the above reaction, the ${{\Delta }_{r}}H$value will be: (given, $\Delta H$of sublimation for ${{N}_{2}}{{O}_{5}}$is $54kJ\,mo{{l}^{-1}}$)     AIEEE  Solved  Paper (Held On 11 May  2011)

A)  +54kJ

B)  +219kJ

C)  -219kJ

D) -165kJ

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