Solved papers for JEE Main & Advanced AIEEE Paper (Held On 11 May 2011)

done AIEEE Paper (Held On 11 May 2011) Total Questions - 2

• question_answer1) The value of enthalpy change \[(\Delta H)\]for the reaction\[{{C}_{2}}{{H}_{5}}O{{H}_{(l)}}+3{{O}_{2(g)}}\to 2C{{O}_{2(g)}}+3{{H}_{2}}{{O}_{(l)}}\]at 27°C is  \[-1366.5\text{ }kJ\text{ }mo{{l}^{-1}}.\]The value of internal energy change for the above reaction at this temperature will be :     AIEEE  Solved  Paper (Held On 11 May  2011)
  A)
  -1369.0 kJ        
  done clear
  B)
  -1364.0kJ        
  done clear
  C)
  -1361.5 kJ        
  done clear
  D)
  -1371.5 kJ
  done clear
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• question_answer2) Consider the reaction : \[4N{{O}_{2(g)}}+{{O}_{2(g)}}\to 2{{N}_{2}}{{O}_{5}}_{(g)}'\]\[{{\Delta }_{r}}H=-111\,kJ.\] If \[{{N}_{2}}{{O}_{5(s)}}\]is formed instead of \[{{N}_{2}}{{O}_{5(g)}}\]in the above reaction, the \[{{\Delta }_{r}}H\]value will be: (given, \[\Delta H\]of sublimation for \[{{N}_{2}}{{O}_{5}}\]is \[54kJ\,mo{{l}^{-1}}\])     AIEEE  Solved  Paper (Held On 11 May  2011)
  A)
   +54kJ           
  done clear
  B)
   +219kJ         
  done clear
  C)
   -219kJ         
  done clear
  D)
  -165kJ
  done clear
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