Solved papers for JEE Main & Advanced JEE Main Paper (Held On 26 May 2012)

done JEE Main Paper (Held On 26 May 2012) Total Questions - 1

• question_answer1) The electrical resistance R of a conductor of length \[l\] and area of cross section a is given by\[R=\frac{\rho l}{a}\]where \['\rho '\]is the electrical resistivity. What is the dimensional formula for electrical conductivity' \['\sigma '\]which is reciprocal of resistivity?   JEE Main Online Paper (Held On 26-May-2012)  
  A)
  \[[{{M}^{-1}}{{L}^{-3}}{{T}^{3}}{{A}^{2}}]\]         
  done clear
  B)
                         \[[M{{L}^{-3}}{{T}^{-3}}{{A}^{2}}]\]
  done clear
  C)
                         \[[M{{L}^{-3}}{{T}^{-3}}{{A}^{-2}}]\]       
  done clear
  D)
                         \[[{{M}^{-2}}{{L}^{3}}{{T}^{2}}{{A}^{-1}}]\]
  done clear
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