Solved papers for JEE Main & Advanced JEE Main Paper (Held on 7 May 2012)

done JEE Main Paper (Held on 7 May 2012) Total Questions - 1

• question_answer1) Given that K= energy, V= velocity, T= time. If they are chosen as the fundamental units, then what is dimensional formula for surface tension?   JEE Main Online Paper (Held On 07 May 2012)
  A)
  \[[K{{V}^{-2}}{{T}^{-2}}]\]           
  done clear
  B)
                         \[[{{K}^{2}}{{V}^{2}}{{T}^{-2}}]\]
  done clear
  C)
                         \[[{{K}^{2}}{{V}^{-2}}{{T}^{-2}}]\]                            
  done clear
  D)
                         \[[K{{V}^{2}}{{T}^{2}}]\]
  done clear
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