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JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Afternoon)

  • question_answer
    In a line of sight radio communication, a distance of about 50 km is kept between the transmitting and receiving antennas. If the height of the receiving antenna is 70m, then the minimum height of the transmitting antenna should be: (Radius of the Earth \[=6.4\times {{10}^{6}}m\]).                                                 [JEE Main 8-4-2019 Afternoon]

    A) 40 m               

    B) 51 m

    C) 32 m   

    D)   20 m

    Correct Answer: C

    Solution :

    Range\[=\sqrt{2R{{h}_{T}}}+\sqrt{2R{{h}_{R}}}\] \[50\times {{10}^{3}}=\sqrt{2\times 6400\times {{10}^{3}}\times {{h}_{T}}}\]         +\[\sqrt{2\times 6400\times {{10}^{3}}\times 70}\] by solving \[{{h}_{T}}=32m\]


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