question_answer

The quantum number of four electrons are given below -

I. \[n=4,l=2,{{m}_{l}}=2,{{m}_{s}}={\scriptscriptstyle 1\!/\!{ }_2}\]

II. \[n=3{{,}_{l}}=2,{{m}_{l}}=1,{{m}_{s}}=+{\scriptscriptstyle 1\!/\!{ }_2}\]

III. \[n=4{{,}_{l}}=1,{{m}_{l}}=0,{{m}_{s}}=+{\scriptscriptstyle 1\!/\!{ }_2}\]

IV. \[n=3{{,}_{l}}=1,{{m}_{l}}=1,{{m}_{s}}={\scriptscriptstyle 1\!/\!{ }_2}\]

The correct order of their increasing energies will be -

[JEE Main 8-4-2019 Morning]

A) \[IV<III<II<I\]           

B) \[IV<II<III<I\]

C) \[~I<II<III<IV\]        

D) \[I<III<II<IV\]