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JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Morning)

  • question_answer
    The IUPAC name of the following compound is: \[{{\text{H}}_{\text{3}}}\text{C}-\overset{\begin{smallmatrix}  \text{C}{{\text{H}}_{\text{3}}} \\  \text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{CH}}}\,-\overset{\begin{smallmatrix}  \text{OH} \\  \text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{CH}}}\,-\text{C}{{\text{H}}_{\text{2}}}-\text{COOH}\]             [JEE Main 8-4-2019 Morning]

    A) 2-Methy1-3Hydroxypentan-5-oic acid

    B) 4,4-Dimethy1-3-hydroxy butanoic acid

    C) 3-Hydroxy-4 -methylpentanoic acid

    D) 4-Methy1-3-hydroxypentanoic acid

    Correct Answer: C

    Solution :

    \[\underset{\text{5}}{\mathop{\text{C}}}\,{{\text{H}}_{\text{3}}}-\underset{\text{4}}{\overset{\begin{smallmatrix}  \text{C}{{\text{H}}_{\text{3}}} \\  \text{ }\!\!|\!\!\text{ } \end{smallmatrix}}{\mathop{\text{CH}}}}\,-\underset{\text{OH}}{\mathop{\underset{|}{\overset{3}{\mathop{\text{CH}}}}\,}}\,-\overset{\text{2}}{\mathop{\text{C}}}\,{{\text{H}}_{\text{2}}}-\overset{1}{\mathop{\text{C}}}\,\text{OOH}\] 3-Hydroxy-4-methylpentanoic acid -COOH principal functional group Correct option : (c)


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