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JEE Main & Advanced JEE Main Paper (Held on 08-4-2019 Morning)

  • question_answer
    The equation of a plane containing the line of intersection of the planes \[2xy4=0\] and \[y+2z4=0\]and passing through the point (1, 1, 0) is : [JEE Main 8-4-2019 Morning]

    A) \[x+3y+z=4\]            

    B) \[xyz=0\]

    C) \[x3y2z=2\]

    D)   \[2xz=2\]

    Correct Answer: B

    Solution :

    The required plane is \[\left( 2xy4 \right)+\lambda \left( y+2z4 \right)=0\] it passes through (1, 1, 0) \[\Rightarrow \]\[\left( 214 \right)+\lambda \left( 14 \right)=0\] \[\Rightarrow \] \[33\lambda =0\Rightarrow \lambda =1\] \[\Rightarrow \] \[xyz=0\]


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