A) 2
B) 3
C) 9
D) 4
Correct Answer: A
Solution :
Given \[\sum\limits_{i=1}^{9}{({{x}_{i}}-5)=9}\]and \[\sum\limits_{i=1}^{9}{{{({{x}_{i}}-5)}^{2}}=45}\] Variance \[{{\sigma }^{2}}=\frac{1}{x}\sum\limits_{{}}^{{}}{{{({{x}_{i}}-5)}^{2}}-{{\left[ \frac{1}{x}\sum\limits_{{}}^{{}}{({{x}_{i}}-5)} \right]}^{2}}}\] \[=\frac{1}{9}\times 45-{{\left[ \frac{9}{9} \right]}^{2}}\] \[n=9\] \[{{\sigma }^{2}}=5-1=4\] Standard Derivation \[=\sqrt{4}=2\]
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