A) \[\text{FeC}{{\text{l}}_{\text{3}}}\]
B) \[\text{Pb(C}{{\text{H}}_{\text{3}}}\text{COO}{{\text{)}}_{\text{2}}}\]
C) \[\text{Al(CN}{{\text{)}}_{3}}\]
D) \[\text{C}{{\text{H}}_{\text{3}}}\text{COOK}\]
Correct Answer: D
Solution :
\[\text{C}{{\text{H}}_{\text{3}}}\text{COOK+}{{\text{H}}_{\text{2}}}\text{O}\xrightarrow{{}}\text{C}{{\text{H}}_{\text{3}}}\text{COOH+KOH}\](salt of weak acid and strong base) Option is most basic.
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