A) \[{{C}_{3}}{{H}_{4}}{{O}_{2}}\]
B) \[{{C}_{2}}{{H}_{4}}{{O}_{3}}\]
C) \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]
D) \[{{C}_{2}}{{H}_{4}}O\]
Correct Answer: B
Solution :
Mole ratio of \[\text{C:H}\Rightarrow \frac{6}{12}:\frac{1}{1}\Rightarrow 1:2\] \[{{\text{C}}_{\text{X}}}{{\text{H}}_{\text{y}}}\text{+}\left( \text{x+}\frac{\text{y}}{\text{4}} \right){{\text{O}}_{\text{2}}}\xrightarrow{{}}\text{xC}{{\text{O}}_{\text{2}}}\text{+}\frac{\text{y}}{\text{2}}{{\text{H}}_{\text{2}}}\text{O}\] According to questions \[\text{2z=2}\left( x+\frac{y}{4} \right)........(1)\] \[\frac{x}{y}=\frac{1}{2}..........(2)\] From (1) & (2) \[\] \[{{C}_{x}}{{H}_{y}}{{O}_{z}}\equiv {{C}_{x}}{{H}_{2x}}{{O}_{\frac{3x}{2}}}\equiv {{C}_{2}}{{H}_{4}}{{O}_{3}}\]
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