A) \[{{v}_{L}}/16\]
B) \[{{v}_{L}}/25\]
C) \[25\,\,{{v}_{L}}\]
D) \[16\,\,{{v}_{L}}\]
Correct Answer: B
Solution :
\[h{{v}_{L}}=13.6{{z}^{2}}\left( \frac{1}{1}-\frac{1}{\infty } \right)\] \[hv=13.6{{z}^{2}}\left( \frac{1}{25}-\frac{1}{\infty } \right)\] \[\Rightarrow v=\frac{{{v}_{L}}}{25}\]
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