A) \[\text{ }\!\![\!\!\text{ Co(}{{\text{H}}_{\text{2}}}\text{O}{{\text{)}}_{\text{4}}}\text{C}{{\text{l}}_{\text{2}}}\text{ }\!\!]\!\!\text{ Cl}\text{.2}{{\text{H}}_{\text{2}}}\text{O}\]
B) \[\text{ }\!\![\!\!\text{ Co(}{{\text{H}}_{\text{2}}}\text{O}{{\text{)}}_{\text{3}}}\text{C}{{\text{l}}_{\text{3}}}\text{ }\!\!]\!\!\text{ }\cdot \text{3}{{\text{H}}_{\text{2}}}\text{O}\]
C) \[\text{ }\!\![\!\!\text{ Co(}{{\text{H}}_{\text{2}}}\text{O}{{\text{)}}_{\text{6}}}\text{ }\!\!]\!\!\text{ C}{{\text{l}}_{\text{3}}}\]
D) \[\text{ }\!\![\!\!\text{ Co(}{{\text{H}}_{\text{2}}}\text{O}{{\text{)}}_{\text{5}}}\text{Cl }\!\!]\!\!\text{ C}{{\text{l}}_{\text{2}}}\text{.}{{\text{H}}_{\text{2}}}\text{O}\]
Correct Answer: B
Solution :
\[\Delta {{T}_{f}}=i{{k}_{f}}m\] \[{{T}_{{{f}_{solvent}}}}-{{T}_{{{f}_{solution}}}}=i{{k}_{f}}m\] For highest freezing point Vant hoff factor (i) should be lowest.
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