A) 2 s
B) 5s
C) 2.5 s
D) 3 s
Correct Answer: A
Solution :
Given moment of inertia \['I'=1.5kg{{m}^{2}}\] Angular Acc. \[''\alpha ''=20\text{ }Rad/{{s}^{2}}\] \[KE=\frac{1}{2}I{{\omega }^{2}}\] \[1200=\frac{1}{2}1.5\times {{\omega }^{2}}\] \[{{\omega }^{2}}=\frac{1200\times 2}{1.5}=1600\] \[\omega =40rad/{{s}^{2}}\] \[\omega ={{\omega }_{0}}+\alpha t\] \[40=0+20t\] \[t=2\sec .\]
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