A) 2.0 pm
B) 2.0 nm
C) 1.0 pm
D) 0.1 nm
Correct Answer: A
Solution :
Millimoles \[=10\times {{10}^{3}}={{10}^{2}}\] Moles \[={{10}^{5}}\] No. of molecules \[=6\times {{10}^{23}}\times {{10}^{5}}=6\times {{10}^{+18}}\] surface area occupied by one molecule \[=\frac{0.24}{6\times {{10}^{18}}}=0.04\times {{10}^{-18}}c{{m}^{2}}\] \[4\times {{10}^{-20}}={{a}^{2}}\] \[a=2\times {{10}^{-10}}\,cm=2pm\]
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