A) \[\text{14g of }{{\text{N}}_{\text{2}}}\text{+4g of }{{\text{H}}_{\text{2}}}\]
B) \[\text{28g of }{{\text{N}}_{\text{2}}}\text{+6g of }{{\text{H}}_{\text{2}}}\]
C) \[\text{56g of }{{\text{N}}_{\text{2}}}\text{+10g of }{{\text{H}}_{\text{2}}}\]
D) \[\text{35g of }{{\text{N}}_{\text{2}}}\text{+8g of }{{\text{H}}_{\text{2}}}\]
Correct Answer: C
Solution :
\[{{N}_{2}}(g)+3{{H}_{2}}(g)\to 2N{{H}_{3}}(g);\] [a]\[\begin{matrix} \underset{(LR)}{\mathop{0.5mol}}\, & 2mol \\ \end{matrix}\] [b]\[\begin{matrix} 1mol & 3mol & (completion) \\ \end{matrix}\] [c] \[\begin{matrix} 2mol & \underset{(LR)}{\mathop{5mol}}\, \\ \end{matrix}\] [d] \[\begin{matrix} \underset{(LR)}{\mathop{1.25mol}}\, & \underset{{}}{\mathop{4mol}}\, \\ \end{matrix}\] \[\therefore \] Ans. [c]
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