A) \[3.75\text{ }\times \text{ }{{10}^{6}}\]
B) \[4.87\text{ }\times \text{ }{{10}^{5}}\]
C) \[6.25\text{ }\times \text{ }{{10}^{5}}\]
D) \[3.86\text{ }\times \text{ }{{10}^{6}}\]
Correct Answer: C
Solution :
No. Of channels \[=\,\,\frac{f}{B.W}\] \[n\,\,=\,\,\,\frac{\frac{3\times {{10}^{8}}}{800\times {{10}^{-9}}}\times \frac{1}{100}}{6\,\times {{10}^{6}}}\] \[n\,\,=\,\,\,\frac{3\times {{10}^{17}}}{8\times 6\,\times {{10}^{6}}\times {{10}^{4}}}\,\,=\,\,\frac{10}{2\times 8}\,\,=\,\,\frac{100}{16}\,\times {{10}^{5}}\] \[=\,\,6.25\times {{10}^{5}}\]
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