A) 100 N
B) 70 N
C) 140 N
D) 200 N
Correct Answer: A
Solution :
\[\frac{f}{\sin \,(180{}^\circ -45{}^\circ )}\,\,=\,\,\frac{Mg}{\sin \,(90{}^\circ +45{}^\circ )}\] \[\frac{f}{\sin \,45{}^\circ }\,\,=\,\,\frac{Mg}{\cos \,45{}^\circ }\] \[\Rightarrow \,\,\,f=Mg=10g=100\,N\]You need to login to perform this action.
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